Aim: To test the sample values are consistent with the population variance 64.
Null Hypothesis:H0: The population variance s2 = 64 for the exam scores.Alternate Hypothesis:H1: The population variance s2 ¹ 64 for the exam scores.Basic Situation and assumptions:To test the variance of single sample of 25 exam scores.
The sample are assumed as random and from Normal population N (m,s2) with population Mean m and population variance s2. S2 is the sample variance and is the Sample mean.Test Statistic:The appropriate test statistic to test a single sample variance is Chi-square test.
~ under H0.Here n = sample size, S2 = Sample variance and is the variance to be tested.Level of Significance: The level of significance of the test is 5% Calculation of Sample Mean and Sample Variance:Sample Variance = S2 = and sample mean = =Sample Mean:== (80+79+69+71+74+73+77+75+65+52+81+84+84+79+70+78+62+77+88+70+75+85+84) / 25= 1877 / 25= 75.08Hence the Sample Mean of exam scores = 75.08We can work out the alternate formula for easy calculation as followsS2 =3 xi2 = 802+792+692+712+742+732+772+752+652+522+812+842+842+792+702+782+622+772+882+702+ 752+852+842 = 142505S2 ==Hence substituting the values in the test statistic= Decision:This is a two tailed test since the variance may be less than or greater than 64.
At 5% significance level of significance we have to look for the upper 2.5% and lower 2.5% points of the Chi-square distribution table with 24 degrees of freedom.The lower 2.5% and upper 2.5% points of are 12.
4 and 39.36.Our test statistic value 24.685 lies in the above interval (12.4, 39.36).
Hence at 5% level of significance we have insufficient evidence to reject the null hypothesis and also the p-value for the test statistic is 0.8461 which is large enough than 0.05 and hence H0 withstands.Conclusion:As we have insufficient evidence to reject the null hypothesis, we can conclude that the sample values of 25 exam scores are consistent with the true variance 64. Appendix:Critical points of Chi-square distribution. The Mega stat analysis in Excel 2003.